1/2t-t^2=1/2

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Solution for 1/2t-t^2=1/2 equation: 



1/2t-t^2=1/2

We move all terms to the left:

1/2t-t^2-(1/2)=0



Domain of the equation: 2t!=0

t!=0/2

t!=0

t∈R



We add all the numbers together, and all the variables

-t^2+1/2t-(+1/2)=0

We add all the numbers together, and all the variables

-1t^2+1/2t-(+1/2)=0

We get rid of parentheses

-1t^2+1/2t-1/2=0

We calculate fractions


-1t^2=0

a = -1; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-1)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$t=\frac{-b}{2a}=\frac{0}{-2}=0$

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